![]() How to get a character pointer that's valid while x remains in scope and isn't modified furtherĬ++11 simplifies things the following all give access to the same internal string buffer: const char* p_c_str = x.c_str() Ĭhar* p_writable_data = x.data() // for non-const x from C++17Ĭhar* p_x0_rw = &x // compiles iff x is not const.Īll the above pointers will hold the same value - the address of the first character in the buffer. In simple terms, our program has converted the characters T and F to strings.Getting a `char *` or `const char*` from a `string` “The second monogram letter is: “ is printed to the console, followed by the value stored in the variable second_string. ![]()
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